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9c-15c^2=0
a = -15; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-15)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-15}=\frac{-18}{-30} =3/5 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-15}=\frac{0}{-30} =0 $
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